https:\/\/www.codewars.com\/kata\/52fba66badcd10859f00097e\/train\/javascript<\/a><\/p>\n\n\n\n Trolls are attacking your comment section!<\/p>\n\n\n\n A common way to deal with this situation is to remove all of the vowels from the trolls’ comments, neutralizing the threat.<\/p>\n\n\n\n Your task is to write a function that takes a string and return a new string with all vowels removed.<\/p>\n\n\n\n For example, the string “This website is for losers LOL!” would become “Ths wbst s fr lsrs LL!”.<\/p>\n\n\n\n Note: for this kata The code:<\/p>\n\n\n\n It could be made shorter by using regular expressions but regex is its own meta-language.<\/p>\n\n\n\n It could argued that it would be made more clear by doing only one operation per line and using traditional functions declaration and for loops, but I am siding with the modern vs the traditional here:<\/p>\n\n\n\n e.g.<\/p>\n\n\n\n Links to MDN articles discussing the techniques used here:<\/p>\n\n\n\n https:\/\/developer.mozilla.org\/en-US\/docs\/Web\/JavaScript\/Reference\/Functions\/Arrow_functions<\/a><\/p>\n\n\n\n https:\/\/developer.mozilla.org\/en-US\/docs\/Web\/JavaScript\/Reference\/Operators\/Destructuring_assignment<\/a><\/p>\n\n\n\n https:\/\/developer.mozilla.org\/en-US\/docs\/Web\/JavaScript\/Reference\/Global_Objects\/Array\/filter<\/a><\/p>\n\n\n\ny<\/code> isn’t considered a vowel.<\/p>\n\n\n\ndisemvowel=s=>[...s].filter(c=>!\"aeiouAEIOU\".includes(c)).join('')<\/code><\/pre>\n\n\n\nfunction disemvowel(s){\n output = \"\";\n for(i=0;i<s.length;i++){\n if(!\"aeiouAEIOU\".includes(s[i])){\n output += s[i]; \n }\n }\n return output;\n}<\/code><\/pre>\n\n\n\n